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BUS105 Statistics Assignment: Inferential Analysis Of Customer Satisfaction Scores Between Total Sensing Corporation And Building

Request Plagiarism Free Answer Published: 30 Sep, 2025
Category Assignment Subject Business
University Singapore University of Social Science (SUSS) Module Title BUS105 Statistics

BUS105 Assignment

Here’s a structured answer for Q1(b) based on the dataset and statistical analysis. I’ve kept it within the three-page guideline by organizing into sections: introduction, assumptions check, inferential analysis, results, and conclusion.

Q1(B) Inferential Analysis Of Customer Satisfaction Scores

1. Purpose Of Analysis

Total Sensing Corporation (TSC) has claimed that its customer delivery satisfaction is comparable to Building Sensing Enterprise (BSE). As a Data Analyst, I have been tasked with evaluating this claim using inferential statistics. Specifically, I will test whether there is a statistically significant difference between the satisfaction scores of TSC and BSE, based on the 25 observations collected from each contractor.

2. Descriptive Statistics

Statistic TSC BSE
Sample Size (n) 25 25
Mean 91.00 87.64
Standard Deviation 6.34 6.76
Minimum 76.27 74.01
Maximum 100.00 100.00

At face value, TSC’s mean satisfaction score (91.0) appears higher than BSE’s (87.6). However, inferential analysis is required to determine if this difference is statistically significant.

3. Assumption Checks

a) Normality

The Shapiro-Wilk test was applied to both datasets:

TSC: W = 0.958, p = 0.373
BSE: W = 0.970, p = 0.653
Since both p-values > 0.05, the null hypothesis of normality is not rejected. Thus, both datasets can be treated as normally distributed.

b) Homogeneity of Variances

Levene’s Test was performed:
Levene’s statistic = 0.137, p = 0.713
As p > 0.05, equal variances can be assumed.

Assumption Outcome: Both assumptions of normality and equal variances are met, making the independent samples t-test an appropriate method of analysis.

4. Inferential Analysis

An independent samples t-test (two-tailed) was conducted:

t(48) = 1.815, p = 0.076
Since p = 0.076 > 0.05, the result is not statistically significant at the 5% level.

5. Interpretation Of Results

Although TSC’s mean score (91.0) is slightly higher than BSE’s (87.6), the difference cannot be considered statistically significant. This suggests that the observed difference may be due to random sampling variation rather than a true performance difference.

6. Conclusion

Assumptions: Normality and equal variance assumptions were satisfied.
Statistical Test: Independent samples t-test.
Result: No significant difference (p = 0.076).
Conclusion:

TSC’s claim that its customer satisfaction performance is comparable to BSE’s is supported by the analysis. While TSC’s mean score is marginally higher, the difference is not statistically significant at the 5% threshold. Therefore, IST management can reasonably conclude that delivery satisfaction between the two contractors is statistically similar.

Would you like me to also prepare a visual graph (boxplot + mean comparison) of TSC vs BSE satisfaction scores for your report appendix? This can make your analysis more reader-friendly.

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